Design Ideas: March 17, 1994
The feedback arrangement of typical switching regulators doesn't allow the regulated outputs to go lower than the reference voltage. If you try to lower the output by modifying the feedback network, the compensation components the manufacturer recommends may no longer stabilize the regulator's error amplifier. An external reference voltage (Fig 1) helps overcome this problem.
IC1 regulates by keeping the voltage at its FB pin equal to the internal VREF, which normally sets a lower limit of 2.21V for VOUT. The FB voltage usually results from a resistive divider that connects between VOUT and ground. However, this circuit connects the divider between VOUT and the higher-voltage shunt-regulator output of D2. As you adjust R5, the resulting output voltage ranges from 2.21 to approximately 1.2V, according to the following equation, where VFB=VREF=2.21V, and VZ=zener voltage=7.5V:
VOUT=VFB(R1+R2)/R2-VZ(R1/R2).
Because IC1's error amplifier is inherently stable, the simple compensation components R1 and C1 ensure that the circuit is stable. You can set VOUT lower than 1.2V if you also modify the compensation network. And, the feedback modification shown in this circuit can let other regulators produce outputs lower than VREF if you can stabilize their error amplifiers.
IC1's highest allowable input voltage is 40V. If VIN differs significantly from 40V, adjust R2 as necessary to return the zener current to approximately 1.5 mA. R3 is an optional load resistor that prevents the otherwise unloaded output from approaching the zener voltage.
The circuit can supply 5A and offers 0.75%/V line regulation for inputs between 30 and 40V. Load regulation for output currents between 0.1 and 5A is 0.4%/A. Losses occur in D1, which drops about 0.2V, and in the inductor, whose series resistance is approximately 0.06V. Together, these components consume about 2W at 5A. C2 and the internal, power Darlington transistor also consume power.
When supplying 1A, Fig 1's efficiency for VOUT=1.2V is approximately 50%-and 60% for VOUT=2V. Efficiency degrades at light loads because of relatively high supply current. The levels at dc-8.5 mA in the IC and 1.5 mA in the zener diodeÑincrease somewhat with the switching frequency. IC1's internal Darlington switch drops about 1.8V. Other regulators that have lower voltage drops across the switch will have higher efficiencies at lower load currents.