Design Ideas: June 6, 1996
The circuit in Figure 1b overcomes these disadvantages. Unlike simpler approaches, this circuit starts up at an output of 0V. This circuit doesn't add any reactive components to the feedback circuit, which prevents any impact on stability and transient response. The value of RT should be considerably smaller than that of R3 to assure that the junction of RT and CT acts as a voltage source driving R3 and to assure that RT is the primary timing control. If sufficient current flows into the loop summing junction through R3 to generate VADJ>VREF, then VOUT is 0V. As RT charges CT,
VCONTROL decays, which eventually results in VADJ This circuit requires a regulator with an enable function, because a small (less than 2V) spike occurs when you apply a step-function input voltage. C1 and R4 provide the short hold-off time required to eliminate this spike.
If a momentary interruption of input voltage occurs, D1 rapidly discharges CT. The build-up of regulator output voltage is less logarithmic than an RC charge curve, because only an initial portion of the
RC charge waveform is used (the part for which VCONTROL>VREF+0.6V).
The actual time constant in Figure 2 is 0.33 sec, so 3t is 1 sec. As
Figure 2 shows, this provides about 400 msec of ramp time (10 to 90%). The whole curve (0 to 100%, or about 600 msec) corresponds to the first 60% of the capacitor RC charge curve.
You can calculate R3 as follows. At turn-on time, force VADJ=1.5V (just slightly higher than VREF). Then, ICONTROL=1.5V/[(R1 X R2)
/(R1+R2)] and R3=(VIN(MIN)-0.6V)/ICONTROL. Because IC1 is a low-dropout regulator, 6V was chosen for VIN(MIN). This value corresponds to the small (approximately 40 msec) delay before the output begins to rise. With a 7V input, the initial delay is considerably more noticeable. (DI #1875)
Figure 2 illustrates the input and output waveforms for the circuit in Figure 1b. The small initial delay (about 40 msec) is the time interval during which VADJ>VREF. Because VIN is usually a fairly consistent value, you can choose R3 to minimize this delay. If you calculate R3 based on the minimum possible
VIN, then higher values of VIN produce additional delay before the turn-on ramp begins. Conversely, if you use the maximum VIN to calculate R3, lower values of VIN do not produce the desired turn-on characteristic. In this case, there is a small initial step function before the desired turn-on waveform.
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