EDN Access

 

May 8, 1997


Circuit adapts differential input to drive coax

Donald Whitney Jr, Harris Semiconductor, Melbourne, FL

ICs designed for analog and digital signal processing are migrating to lower voltage processes. Analog signals must therefore use differential lines to achieve adequate dynamic range. However, cable-modem and video applications require single-ended signal transmission through a coaxial cable. Moreover, the signal levels are higher than the level a typical op-amp driver with a series termination resistor can provide. The line driver in Figure 1 uses an HFA1100 or HFA1105 to convert a balanced input signal to a single-ended output signal. The circuit synthesizes the back-termination impedance to provide a matched termination to the coax load.

Positive feedback synthesizes the desired back-termination impedance, using the series resistor, RM, which has a lower value than does ZO. The voltage drop, or signal loss, across RM is less than it would be for a line-driver circuit that uses a series back-termination resistor of value ZO. A larger voltage swing is thus possible at the load. The positive feedback causes the amplifier to make up the difference between RM and ZO. Moreover, the addition of R6 makes it possible to achieve equal gains from V IN+ to VOUT and from VIN­ to VOUT. Assuming that the amplifier has high open-loop gain, you can determine the resistor values by using the following equations and parameters. First, define the parameters:

  • AOF is the gain from VIN+ to VOUT or VIN­ to VOUT when ZO=ZL;

  • ZO is the desired back-termination impedance of the positive-feedback circuit;

  • ZL is the load impedance;

  • VOUTP is the peak desired output voltage at VOUT;

  • VOP is the peak op-amp output voltage at VO.

The input resistance at VIN­ is a function of R3, so make this resistance as high as the bandwidth considerations allow--usually 300 to 700 ohms for the HFA1100 or HFA1105. Set R6 as low as possible to keep the input resistance at VIN close to the value at VIN­--usually 300 to 1000V. You can calculate the remaining resistors from the following equations:

The peak output voltage, VOUTP, cannot be higher than the peak output current times the load impedance, ZL. Also, as the gain, AOF, and the ratio of ZO to RM increase, the required closed-loop gain, ACL, increases, thereby limiting the attainable bandwidth of the line driver. Table 1 gives calculated ACL values for some given RM and AOF values. Table 2 gives component values for AOF=2 (differential gain of 4) and ZO=75 ohms. Figure 2 shows both the amplifier voltage and the load voltage. The positive feedback increases the available load voltage from 1.4VPK (2.8VPK/2) to 2.1VPK. (DI #2024)


Table 1--Closed-loop gain vs RM and AOF
RM
(ohms)
AOF ACL
5 1 7.2
25 1 4.5
50 1 3.5
25 2 6.4
50 2 5.6
Table 2--Typical design example
Variables Values
AOF 2
ZO 75 ohms
ZL 75 ohms
VOP 2.8VPK
VOUTP 2.1VPK
RM 25 ohms
R1 175 ohms
R2 312.5 ohms
R3 667V
R4 500V
R6 700V

Figure 1
Positive feedback provides characteristic-impedance matching while increasing the available output swing, as compared with using a simple series termination resistor.
Figure 2
The positive-feedback scheme of the circuit in Figure 1 provides a 50% increase in output swing at the load, referred to the op amp's output voltage.

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