Add extra output to a boost converter
Vladimir Oleynik, Moscow, Russia; Edited by Paul Rako and Fran Granville - November 17, 2011
Designers use step-up-converter
ICs in battery-powered portable
equipment. These chips usually provide
one output with a fixed or an adjustable
voltage. Some chips contain an LBI/LBO (low-battery-in/low-battery-out)
function. The chip manufacturer
intends for these pins to be used for
monitoring a low-battery condition and
to warn gadget owners when a battery
goes flat. You can instead use this function
to provide an extra voltage output.

You can use these components to
make a second output with a regulated
voltage (Figure 2). R1 and R2 determine
the secondary output voltage according
to the following equation: Output 2
=VREF(R1+R2)/R2, where VREF is the reference
voltage, which is 1.25V for this
chip.

You can set Output 2 from 1.25 to
5V as long as it is less than Output
1. Because Output 2 is derived from
Output 1, the total output current for
both outputs should not exceed 200
and 300 mA for Output 1 and Output
2 voltages of 5 and 3.3V, respectively.

You can also use the LBI/LBO function
to make a second boost converter
(Figure 3). The CD4093 quad Schmitt-triggered
NAND gates, inductor L2, R2
through R4, Q1, D1, C1, and C2 compose
this boost converter. Add C1 and R2 to
IC1B to make a free-running oscillator
that IC1A gates on. For the values of
R2 and C1 in the figure, the oscillator
frequency is approximately 17 kHz. R1
pulls up the open-drain LBO output.
When the voltage at the LBI pin
is lower than 1.25V, the LBO pin is
low, thus allowing operation of the
IC1B oscillator. IC1C and IC1D drive power MOSFET transistor Q1. When Q1 is on, it pulls
current from inductor L1. When Q1 is off, this energy
charges capacitor C2 through flyback diode D1. You apply
feedback with resistor divider R3 and R4 to determine
the Output 2 voltage, according to the following equation:
Output 2=1.25V×(R3+R4)/R4. IC1 gets power from
Output 1.
The voltage at Output 2 is a function of the output current
and the input voltage (Figure 4). If you have adequate input
voltage, the output graph shows a flat section where the IC’s
regulation is effective (figures 5 and 6).

The Maxim MAX756 boost converter
provides a fixed output of 3.3 or
5V at 300 and 200 mA, respectively
(Figure 1). The input voltage can
range from 0.7 to 5.5V. For low-battery
detection, the part has on-chip circuitry
comprising a comparator, a reference,
and an open-drain MOSFET. When
the voltage at the LBI input is lower
than its threshold level of 1.25V, the
MOSFET at the LBO output sinks current
to ground.

You can use these components to
make a second output with a regulated
voltage (Figure 2). R1 and R2 determine
the secondary output voltage according
to the following equation: Output 2
=VREF(R1+R2)/R2, where VREF is the reference
voltage, which is 1.25V for this
chip.

You can also use the LBI/LBO function
to make a second boost converter
(Figure 3). The CD4093 quad Schmitt-triggered
NAND gates, inductor L2, R2
through R4, Q1, D1, C1, and C2 compose
this boost converter. Add C1 and R2 to
IC1B to make a free-running oscillator
that IC1A gates on. For the values of
R2 and C1 in the figure, the oscillator
frequency is approximately 17 kHz. R1
pulls up the open-drain LBO output.
When the voltage at the LBI pin
is lower than 1.25V, the LBO pin is
low, thus allowing operation of the
IC1B oscillator. IC1C and IC1D drive power MOSFET transistor Q1. When Q1 is on, it pulls
current from inductor L1. When Q1 is off, this energy
charges capacitor C2 through flyback diode D1. You apply
feedback with resistor divider R3 and R4 to determine
the Output 2 voltage, according to the following equation:
Output 2=1.25V×(R3+R4)/R4. IC1 gets power from
Output 1.
The voltage at Output 2 is a function of the output current
and the input voltage (Figure 4). If you have adequate input
voltage, the output graph shows a flat section where the IC’s
regulation is effective (figures 5 and 6).
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