Designing fast, isolated microamp current sources: Part 1

& -May 16, 2017

In order to test and characterize optical front end circuits, a controllable, high bandwidth, microamp-level current source is needed. However, most optocouplers on the market have large CTR variation, making them unsuitable. Using transistors to build current sources is one of the options. However, they can’t provide a floating output like photodiodes.

One solution to this problem is the HCNR200/201 high-linearity optocoupler from Broadcom (previously Avago Technologies). Unlike most optocouplers, the HCNR200/201 exhibits high linearity and stable gain characteristics, which makes it an excellent solution for floating current source design. Similar optocouplers are available from other manufacturers.

It achieves the high-linearity by illumi­nating two closely matched photodiodes using a high-performance AlGaAs LED (Figure 1). When a feedback network is used, the input pho­todiode (PD1 in Figure 1) can be used to monitor, and therefore stabilize, the light output of the LED. As a result, the non-linearity and drift characteristics of the LED can be virtually elimi­nated.


Figure 1 HCNR200/201 internal circuit diagram

The datasheet of HCNR200/201 provides various circuit topologies to meet many low frequency design requirements such as high accuracy, offset-cancelling, and bipolarity. However, it has little information on how to address dynamic design challenges such as stability, bandwidth, step response, THD, noise, and PSRR. This article uses one of the circuit topologies in the datasheet as an example to go through the design process for all the dynamic requirements mentioned above. Readers can also apply the same analysis process and design techniques in this article to other topologies.


Low frequency operation

Figure 2 shows a basic circuit using HCNR200/201 to generate a current that is highly linear to the input voltage.

Figure 2 Basic application circuit

When VIN is applied, the voltage at negative input of the left side op-amp tends to increase. This causes the op-amp’s output to go low, which draws current from the LED. As the current flows through the LED, a proportional current will also flow through photodiode, PD1. The photodiode current loads R1 more and more until the voltages at the op-amp’s negative and positive inputs are virtually the same, which is 0V in this case.

By applying KCL to the op-amp’s negative input, we have I_PD1 = VIN / R1. Because the PD2 and PD1 are arranged in a way to receive the same amount of light from the LED, I_PD2 = I_PD1 = VIN / R1.

This formula shows that the output current I_PD2 is independent from the optocoupler’s transfer characteristics as long as the feedback is strong enough. Therefore, a stable and linear relationship between input voltage and output current is established.

However, the circuit in Figure 2 may not be stable. The optocoupler has at least two poles: one formed by R1 and the parasitic output capacitor of PD1, and the other one from the optocoupler’s own limited bandwidth, 9MHz. The op-amp also has a pole. That makes 3 poles for the circuit’s open-loop transfer function, meaning the circuit may not be stable.

To stabilize the circuit, circuit in Figure 3 was introduced in HCNR200/201’s datasheet [1].

Figure 3 Practical circuit

C1, R3, and R1 all play essential roles in the compensation, and impact the circuit’s dynamic performances. In next session, we will study how to design C1, R3, and R1 to stabilize the circuit.

The right part of the circuit (network around A2) is a typical TIA configuration. There are sufficient documents analyzing this type of circuit [3]. Therefore, the article will not cover, but only emphasize the input circuitry, the one on the left side in Figure 3.


Stability and compensation

To calculate for stability, we first obtain the circuit’s both forward and feedback paths’ transfer functions. For the sake of analysis we redraw the circuit network in Figure 4. We denote the output of the op-amp A1 as system output, VOUT. The op-amp subtracts two signals, and amplifies the error. The rest of the circuits form the feedback network. This network has two inputs: VIN and VOUT. V- is the output of the feedback network.

Figure 4 Feedback network in the circuit

We then can draw a system diagram (Figure 5) based on the network in Figure 4. The system forward path’s gain A is the op-amp’s open-loop gain, and feedback gain β1 is the feedback network’s transfer function between V- and VOUT when VIN is set to 0, while β2 is the feedback network’s transfer function between V- and VIN when VOUT is set to 0. [3]

Figure 5 System diagram

Since A is the open-loop gain of an op-amp, the system will be stabile if β1 has 0ᵒ phase shift and a less-than-0dB gain at A’s crossover frequency. Of course, commercial op-amps usually is design with some margin, and thus can tolerate some phase shift and gain from β1. But a 0ᵒ phase shift and a less-than-0dB gain is a good and safe starting point. Also, this surmises that A is unit gain stable. If not, β1 has to have an even lower gain to accommodate that.

To acquire β1’s transfer function, the feedback network’s equivalent small signal circuit is drawn in Figure 6. In the circuit, VIN is grounded. The LED is treated as a DC voltage drop. This gives good approximation if R3 is large enough. We will discuss the effect of a small R3 in later sessions. COUT is the parasitic output capacitor of PD1. K is the current gain of the opotocoupler, which is at about 0.5% at low frequency.


Figure 6 Small signal equivalent circuit of the feedback network

Applying KCL and KVL to the circuit, we get:



Solving the functions above, we arrive at the transfer function of the feedback network:


Note that the current gain K is not a constant across frequency, but has a pole at 9 MHz. Hence,


Where K0 is the low frequency gain of K, and ωK = 2π·9 MHz.

We model the op-amp as a single pole system with a crossover angular frequency at ωc. Then, a phase shift of 0ᵒ from β1 indicates that ωc is at a much higher frequency than β1’s zeros and the poles. We therefore can write β1 at ωc as:


That means, β1 always has a gain smaller than 0dB at ωc.

This result can be intuitively observed on the circuit. At high frequency, the K becomes a small number due to its pole at 9 MHz, causing the photonic current at output negligible. Meanwhile, the capacitive currents through C1 and COUT increase with frequency, making current though R1 also insignificant. As a result, the output voltage is only determined by the voltage divider formed by C1 and COUT.

To guarantee that the zeros and poles are at much lower frequencies than ωc, we have


If ωc is much higher than 9 MHz, K(ωc) can be approximated by K0 ωK c .

Those two equations are then the design constrains to select R1, C1, and R3 to ensure system stability.

There is a point worth pointing out: even though the feedback network has more than one pole, we can compensate it using only one capacitor, because the current gain K will cancel itself at frequencies much higher than the zero frequency determined by K/R3C1.

The equations above tells us that to design a more stable system, we can increase R1, C1, or R3, choose an op-amp with high crossover frequency, or even put extra capacitor in parallel with COUT. All those methods can help stabilize the system. In Part 2, we'll explore how those parameters will impact the circuit’s performance beyond stability.




Loading comments...

Write a Comment

To comment please Log In