Single IC provides gains of 10 and –10
Moshe Gerstenhaber and Charles Kitchin, Analog Devices, Wilmington, MA -- 8/7/2003
Real-world data-acquisition systems require amplifying weak signals to match the full-scale input range of an A/D converter. Unfortunately, when you configure them as gain blocks, most common amplifiers have both gain errors and offset drift. The typical two-resistor gain-setting arrangement found in many op-amp circuits has serious accuracy and drift limitations. With standard 1% resistors, the circuit gain can be off by as much as 2%. Also, the gain can vary with temperature, because each resistor drifts differently. You can use monolithic resistor networks for precise gain setting, but these components are expensive and consume valuable pc-board space. The circuits of Figure 1 and Figure 2 offer improved performance and lower cost; they are also smaller. The single-µSOIC approach is the smallest available for this function, and the circuits require no external components. Figure 1 shows an AD628 precision gain block connected to provide a voltage gain of 10. The gain block itself comprises two internal amplifiers: a gain-of-0.1 difference amplifier, A1, followed by an uncommitted buffer amplifier, A2. You can configure it to provide different gains by strapping or grounding the appropriate pins.
For a gain of 10, the input signal connects between the VREF pin (Pin 3) and ground, instead of to the op amp's inputs. With the input tied to the VREF pin, the voltage at the noninverting input of A1 equals VIN(100 kΩ/110 kΩ), or VIN(10/11). The inverting input of A2 (Pin 6) is grounded; therefore, feedback from the output of A2 forces the noninverting input of A2 to be 0V. The output of A1 must then also be at 0V. The voltage on the inverting input of A1 must be equal to the voltage on the noninverting input of A1, so both equal VIN(10/11). Thus, the output voltage of A2, VOUT, equals

providing a precise gain of 10 with no external components.
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