Charge your SAR-converter inputs
By Bonnie Baker -- 5/11/2006
It is tempting to drive a SAR (successive-approximation register) ADC with just an amplifier. As an added benefit, you might try to configure the amplifier circuit in a gain or antialiasing-filter stage. These enhancements seem reasonable as you try to optimize your device use. However, did you think about whether you would compromise the effectiveness of your op-amp/converter pair (Figure 1)?
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If you need good, accurate performance at dc as well as ac, regardless of your throughput rate, the analog-input stage of the SAR ADC requires special attention. The model of the input stage of most modern ADCs is a resistor/capacitor pair with two switches and a voltage source (Figure 2). The resistance, RSW, in the converter's input is the closed-switch resistance. This switch closes during the acquisition time of the conversion process and opens during the conversion time. The converter uses capacitance, CSH, which is the total of the distributed on-chip capacitance, for the input-signal-sampling process.
First and foremost, you need to give sample capacitor CSH enough charging time to reach at least ½LSB of the final value. Theoretically, for a 12-bit converter, enough time would be more than eight times RSW×CSH. Given error margins and component variations, you should use multiples of 10 to 15. The SAR converter needs an op amp with a gain of ±1V/V, along with an RIN–CIN external resistor/capacitor pair. During sampling, the ADC uses capacitor CIN for signal stability. Resistor RIN isolates the amplifier from the ADC's load capacitance. The op amp isolates the ADC from high-impedance loads and drives CIN and CSH, facilitating a quick charge time while the ADC is sampling.
| Author Information |
| Bonnie Baker is the author of A Baker's Dozen: Real Analog Solutions for Digital Designers . You can reach her at bonnie@ti.com. |
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