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Sambo007

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Sambo007

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  • 02.02.2018
  • Buck-boost module teardown & test
  • Are you sure that the input MOSFETs are not switched at high frequency in Boost-Mode? Being located near the Big toroidal coil near them tells me they are part of the boost-mode of the voltage converter.
  • 02.02.2018
  • Buck-boost module teardown & test
  • Hi Michael, Are you sure about your statement: "Dealing with fixed resistances, this wouldn’t happen". I don't see how the FETs behave different than fixed resistors having the same values when you have the same current flowing through! Replace the 2 FETS with two 2mΩ resistors and run the numbers again you will get the same result! Maybe I am confused and not getting your point?! Cheers...
  • 05.11.2016
  • Sensing current on the high side
  • Dear Editor, kindly accept my apology! I did the simulation and realized that you are right! The output is inversely proportional to I. It start at V+ of op-amp and decreases with increase of I of load depending on gain. Obviously, a rail-to-rail I/O op-amp is necessary. I wish this forum allows us to edit/delete our own comments!
  • 05.11.2016
  • Sensing current on the high side
  • Maybe if we flip the op-amp circuit with its resistors around the x-axis, it will work fine. It becomes just like the first circuit omitting R5. But I still can't see how is this better than an Instrumentation Amp?
  • 05.11.2016
  • Sensing current on the high side
  • Sorry! I got the above backward! Let me try again: In the second high-side sense method, when current flows through Rsense the inverting input of the op-amp sees a higher voltage than its non-inverting input. Thus the output of the op-amp will be negative if powered with dual polarity supply! Usually we use single polarity supplies/op-amps in this kind of design! Was that intentional?
  • 05.11.2016
  • Sensing current on the high side
  • In the second high-side sense method when current flows Rsense the inverting input of the op-amp sees a lower voltage than the non-inverting input. Thus the output of the op-amp will be negative!
  • 03.02.2006
  • Simple digital filter cleans up noisy data
  • For those who are interested, I tested the Author's code in the following spreadsheet: LPF - Digital Implementation in Software. https://dl.dropboxusercontent.com/u/5146160/LPF%20-%20Digital%20Implementation%20in%20Software.xlsx
  • 03.02.2006
  • Simple digital filter cleans up noisy data
  • The author specified in advance that the statements are "two lines of C code", not algebraic equations. So LP_ACC on the LHS of the assignment (equal sign in C) is where the new value of the RHS equation will go. Whereas, LP_ACC on the RHS is the previous value. effectively, LP_ACC(n) = LP_ACC(n-1) + LP_IN - LP_OUT. Cheers